Question

По графику уравнения -2x+3y=12 найдите
1) абсциссу точки , ордината которой равна 2
2) ординату точки , абсцисса которой равна 3

Answer 1

1) У = 2,      тогда     -2Х+3х2 = 12                                2) Х =3            -2х3 +3У =12

                -2Х -6 = 12                                                       -6 +3У =12

               -2Х =18                                                                3У =18

                 Х = 18 / -2                                                          У = 18:3

                Х = -9                                                                     У = 6