<span>СaCO3</span> + 2HCl = CaCl2 + H2O +<span>CO2</span>
m(CaCO3)=500 g
M(CaCO3)=100 g/mole
n(CaCO3)= 5 mole
V(CO2)=5*22.4=112 литр
X- доля 203 Tl => 1-x доля 205 Tl