Question

1) 3y2((2y-1)+y + 1 ) - y ( 1 - y + y2 ) - y2 + y =2) a+(2a-c)-a(4a+2) -((a+3a)(-a)-c) =3) ax(-x-2)+x2(3-a)-a(-2(-x)2 - 2x) = 4)1) 3y2((2y-1)+y + 1 ) - y ( 1 - y + y2 ) - y2 + y =
2) a+(2a-c)-a(4a+2) -((a+3a)(-a)-c) =
3) ax(-x-2)+x2(3-a)-a(-2(-x)2 - 2x) =
4) 2(X+1)(X2-X+1)-(2X-1)(x2+3x)-(x-1)(1-5x)

Answer 1

1) = 3y2(2y-1+y+1)-y(1-y+y2)-y2+y = 6y3-3y2+3y3+3y2-y+y2-y3-y2+y = 6y3-y3+3y3 = 4y3
2) = a+2a-c-4a2-2a-(-a2-3a2-c) = a+2a-c-4a2-2a+a2+3a2+c = a
3) = -ax2-2ax+3x2-ax2-a(2x2-2x) = -ax2-2ax+3x2-ax2-2ax2+2x = 2x-4ax2-2ax+3x2
4) = 2(x3+1)-2x3-5x2+3x+5x2-4x+1 = 2x3+2-2x3-5x2+3x+5x2-4x+1 = 1-x