B3 = b1*q^2 ==>
b1*q^2 = 64
b1*(1/2)^2 = 64
b1 = 64 / 0.25
b1 = 256
S7 = (b1*(1 - q^7))/(1 - q) = (256*(1 - (1/2)^7))/(1 - (1/2)) = 508
Решение
cos2x*cosx+cos (6п-x)-sin2x*sinx
cos2x*cosx - sin2x*sinx + cosx = cos3x + cosx =
= 2cos(3x + x)/2 * cos(3x - x)/2 = 2 * cos2x* cosx