Question

(y-2/y+2 + y+2/y-2) : 2y²+8/y²+4y+4

Answer 1

$( \frac{y-2}{y+2} + \frac{y+2}{y-2}): \frac{2 y^{2}+8 }{y^2+4y+4}= \frac{(y-2)(y-2)+(y+2)(y+2)}{(y+2)(y-2)}* \frac{ y^{2}+4y+4 }{2y^2+8} = \\ \\ = \frac{2y^2+8}{(y+2)(y-2)}* \frac{(y+2)(y+2)}{2y^2+8} = \frac{y+2}{y-2}$

Answer 2

((y-2)²+(y+2)²)/((y-2)(y+2))·(y+2)²/(2y²+8)=(2y²+8)/((y-2)(y+2))·(y+2)²/(2y²+8)=(y+2)/(y-2)