(а³-3а²+108-36а)/(а²-9)=0 а≠3 а≠-3
(а²(а-3)+36(3-а))/(а-3)(а+3)=0
(а-3)(а²-36)/(а-3)(а+3)=0
<em>(а-3)</em>(а+6)(а-6)/(а+3)<em>(а-3)</em>=0
(а-6)(а+6)/(а+3)=0
при а=6 и при а=-6 дробь равна 0
Решение:d=1,9;а1=3,9; аn=а1+(n-1)d ;а8=а1+7d
а8=3,9+7*1,9=3,9+13,3=17,2
F'(x)=3x^2-2x
f'(-1)=3+2=5
f(-1)=-1-1+3=1
y=5*(x+1)+1=5x+6
<span>a2 – b2 = (a + b)(a – b),</span>
<span>(a + b)2 = a2 + 2ab + b2,</span>
<span>(a – b)2 = a2 – 2ab + b2,</span>
<span>a3 + b3 = (a + b)(a2 – ab + b2),</span>
<span>a3 – b3 = (a – b)(a2 + ab + b2),</span>
<span><span>an – bn = (a – b)(a<span>n – 1</span> + a<span>n – 2</span>b + a<span>n – 3</span>b2 + … + ab<span>n – 2</span> + b<span>n – 1</span>)</span>,</span>
<span>(a + b)3 = a3 + 3a2b + 3ab2 + b3 = a3 + b3 + 3ab(a + b),</span>
<span>(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b).
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