Х (х-1)(х+1)-(х-2)(х^2+2х+4)=х (х^2-1)-(х^3-8)=х^3-х-х^3+8=8-х
<span> (2√3+1)(2√3-1)
используя (a-b)(a+b)=a^2-b^2 упростим
(2</span>√3)^2-1^2
4*3-1
12-1
11
Ответ:11
(7/3)=(3/7)⁻¹
(3/7)³ˣ⁺¹ =((3/7)⁻¹)⁵ˣ⁻⁹
3х+1=9-5х
3х+5х=9-1
8х=8
х=1
<span>1.
</span>а)-<span>3а+7а-10а=-6а
б)</span>(3х-5)-(-2х+7)=3х-5+2х-7=5х-12
в)<span>-2*(2,5m-1)+3*(m-4)=-5m+2+3m-12=-2m+2
г)</span><span>7а-5b-5a+8b=2a+3b
</span><span>д)2*(3m-n)-9*(m-2n)=6m-2n-9m+18n=-3m+16n
</span>2.
<span>а) -3*1,46+13*1,46=-4,38+18,98=14,6
</span><span>б) 4,57* 4 1/7 - 2,57* 4 1/7=(18,28-10,28)/7=8/7</span>
1. 18а² - 27ab + 14 ac - 21bc = 9а(2а - 3b) + 7c(2a - 3b) = (9a + 7c)(2a - 3b)
2. 6х⁴ - 24х³ = 6х³(х - 4)
3. 4у(6х² - 5у) + 7х (5у - 6х²) - (6х² - 5у) = 4у(6х² - 5у) - 7х(6х² - 5у) - (6х² - 5у) = (4у - 7х - 1)(6х² - 5у)