S(t)=3t²-4t+2
v(t)=S`(t)=(3t²-4t+2)`=3*2t-4=6t-4
v(1)=6*2-4=2
!)3х-4х=1+5
-1х=5
х=5:(-1)
х=5
2)2х+14=9-2х
2х+2х=9-14
4х=-5
х=(-5):4
х=1,25
3)я не поняла ..
Tg (x+π<span>/4) > 1
</span>π/4 + πk < x + π/4 < π/2 + πk , k ∈Z
πk < x < -π/4 +π/2 + πk , k ∈ Z
πk < x < π/4 + πk , k ∈Z
Tg²x - 5 = 4tgx
tg²x - 4tgx - 5 = 0
Пусть tgx = a
a² - 4a - 5 = 0
D = (-4)² - 4*(-5) = 16 + 20 = 36
a₁ = (4 + √36)/2 = (4 + 6)/2 = 5
a₂ = (4 - √36)/2 = (4 - 6)/2 = - 1
tgx₁ = 5 tgx₂ = - 1
x₁ = arctg5 + πn, n ∈ z x₂ = arctg(- 1) + πn, n ∈ z
x₂ = - π/4 + πn, n ∈ z