Ответ простое число это 3
![3cos2x+4+11sinx = 0 \\ 3(1 - 2sin^{2}x) +4+11sinx = 0 \\ 3 - 6sin^{2}x+4+11sinx = 0 \\ - 6sin^{2}x+11sinx+7 = 0 \\ 6sin^{2}x-11sinx-7 = 0 \\ D = 121 + 4*6*7 = 121 + 168 = 289 = 17^{2} \\ sinx = \frac{11 + 17}{12} = \frac{28}{12} \\](https://tex.z-dn.net/?f=3cos2x%2B4%2B11sinx+%3D+0+%5C%5C+%0A3%281+-+2sin%5E%7B2%7Dx%29+%2B4%2B11sinx+%3D+0+%5C%5C+%0A3+-+6sin%5E%7B2%7Dx%2B4%2B11sinx+%3D+0+%5C%5C+%0A-+6sin%5E%7B2%7Dx%2B11sinx%2B7+%3D+0+%5C%5C+%0A6sin%5E%7B2%7Dx-11sinx-7+%3D+0+%5C%5C+%0AD+%3D+121+%2B+4%2A6%2A7+%3D+121+%2B+168+%3D+289+%3D+17%5E%7B2%7D++%5C%5C+%0Asinx+%3D++%5Cfrac%7B11+%2B+17%7D%7B12%7D+%3D+%5Cfrac%7B28%7D%7B12%7D++%5C%5C+)
(невозможно , т.к. | sin x | ≤ 1)
или
![sinx = \frac{11 - 17}{12} = \frac{-6}{12} = - \frac{1}{2}\\ x=(-1)^{n}(-\frac{\pi }{6})+\pi n,](https://tex.z-dn.net/?f=sinx+%3D+%5Cfrac%7B11+-+17%7D%7B12%7D+%3D+%5Cfrac%7B-6%7D%7B12%7D+%3D+-+%5Cfrac%7B1%7D%7B2%7D%5C%5C+%0Ax%3D%28-1%29%5E%7Bn%7D%28-%5Cfrac%7B%5Cpi+%7D%7B6%7D%29%2B%5Cpi+n%2C++)
где n ∈ Z.
![x=(-1)^{n+1}\frac{\pi }{6}+\pi n,](https://tex.z-dn.net/?f=x%3D%28-1%29%5E%7Bn%2B1%7D%5Cfrac%7B%5Cpi+%7D%7B6%7D%2B%5Cpi+n%2C)
где n ∈ Z.
1)4 0 1 2 -5 1/2
2)3 0 1 12 -3 2
3)2 0 1 8 -3 3
4)2 0 1 4 -2 2
5)2 0 1 2 -4 3
6) log₂(20/15*24)=log₂32=5 log₁₄(14²)^1/3=2/3 4*3=12
7) log₃(18*12/8)=log₃27=3 log₇(7²)^1/3=2/3 5*2=10
8) log₄(12/15*20)=log₄16=2 log₆(6³)^1/2=3/2 25*2=50
9) log₅(10/6*15)=log₅25=2 log₈(8²)^1/3=2/3² 8*3=24
10)log₄(28/21*12)=log₄16=2 log₁₆(16²)^1/3=2/3 9/2=4,5
0,49х² - 256у²
(0,7х - 16у) (0,7х + 16у)