Question

X^2+x-12=0 x.1=-46x^2-5x-2=0 x.1=-1/3решите уравнение пж

Answer 1

Х^2+х-12=0
D=1-4(-12)=1+48=49
х1= -1-7/2= -8/2= -4
х2= -1+7/2=6/2=3