5х²-6х=0
х(5х-6)=0
х=0 или 5х-6=0
5х=6
х=6/5
х=1,2
Ответ: х=0; х=1,2
(x-x1)\x2-x1=(y-y1)\y2-y1
(x-2)\-1-2=(y+15)\18+15
-11(x-2)=y+15
-11x+22=y+15
-11x-y=-7
11x+y-7=0
Cos(x-5/(pi2))=cos(х) cos(5/(pi2))+sin(х) sin(5/(pi2))= sinx
<span>если у вас написано 5pi/2 то cos(5pi/2)=0 </span>
<span>sin(5pi/2)=1 </span>
<span>cos(2x)=1-2sin^2(x) </span>
<span>1-2sin^2(x)-sinx-1=0 </span>
<span>sinx(2sinx+1)=0 </span>
<span>sinx=0, </span>
<span>x= n pi </span>
<span>и </span>
<span>sinх= -0.5, </span>
<span>x= -pi/6+2pi n </span>
<span>x= -5pi/ 6+2pi n </span>
- 5b³ + 3b² - (3b² - 2b) = - 5b³ + 3b² - 3b² + 2b = - 5b³ + 2b