Question

(------) делить дробь)))
(x^2,x^3 ) ^2 квадрат,^3 куб
1)x 7 2)2x 3x+1 3 3)5 14 4)6 x 3
---- - ----- = ---- - ---- - ----- = ---- +1= ----- = -------- - ------ - ----- =
x-2 x+2 x-1 x-1 x+1 x-2 x^-4x+4 4x^2-1 2x-1 2x+1

5)a^2-1 3a+2
-------- + ----------- =
a^3+8 a^2-2a+4
плиз помогите срочно!!!!

Answer 1

1)(x(x+2)-7(x-2))/(x²-4)=(x²+2x-7x+14)/(x²-4)=(x²-5x+14)/(x²-4)
2)(2x(x+1)-(3x+1)(x+1)-3(x-1))/(x²-1)=(2x²+2x-3x²-3x-x-1-3x+3)/(x²-1)=
=(-x²-5x+2)/(x²-1)=(x²+5x-2)/(1-x²)
3)(5(x-2)+(x-2)²+14)/(x-2)²=(5x-10+x²-4x+4+14)/(x-2)²=(x²+x+8)/(x²-1)
4)(6-x(2x+1)-3(2x-1))/(4x²-1)=(6-2x²-x-6x+3)/(4x²-1)=(-2x²-7x+9)/(4x²-1)=
=(2x²+7x-9)/(1-4x²)
5)(a²-1+(3a+2)(a+2))/(a³+8)=(a²-1+3a²+6a+2a+4)/(a³+8)=(4a²+8a+3)/(a³+8)