(2х-3)(4+7х)=0
2х-3=0 4+7х=0
2х=3 7х= -4
х= 1,5 х= - 4/7
Log₃3³-log(√3)(√3)⁶-log(1/3)(1/3)^-3-log(√3/2)(√3/2)^-6=3-6+3+6=6
4х²+20х+25+25х²-30х+9-75-2х=0
29х²-12х-41=0
D=144-4*29*(-41)=4900=70²
x1=12+70/58=82/58=41/29=1 12/29
x2=12-70/58=-1
Ответ:-1;41/29(или 1 целая 12/29)