Question

Помогите решить систему уравнений (10а+b)-(a+b)=18 (10a+b)² - a²=480

Answer 1

$\left \{ {{(10a+b)-(a+b)=18} \atop {(10a+b)^2 - a^2=480}} \right. \to \left \{ {{10a+b-a-b=18} \atop {100a^2+20ab+b^2-a^2=480}} \right. \to \left \{ {{9a=18} \atop {99a^2+20ab+b^2=480}} \right. \\ \left \{ {{a=2} \atop {99\cdot 2^2+20\cdot2\cdot b+b^2=480}} \right. \\ b^2+40b-84=0$
По т. Виета
 b1=-42
b2=2

Ответ: $(2;-42),\,\,(2;2).$