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2cos(п-а)+((sin a + tg a )/ tg a )^2 - cos^2 a=-2cosa+(cosa+1)^2-cos^2a=-2cosa+cos^2a+1+2cosa-cos^2a=1
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X⁴-10x³+90x-81=0
(x⁴-81)-(10x³-90x)=0
(x²+9)(x²-9)-10x(x²-9)=0
(x²-9)(x²-10x+9)=0
x²-9=0
x₁=3
x₂=-3
x²-10x+9=0
По т. Виета
x₃=1
x₄= 9
Ответ: -3; 1; 3; 9.