Question

У меня выходит невозможная молярная масса...

Answer 1

CnH2n+1NH2 + HBr = CnH2n+1NH3Br

 

n(CnH2n+1NH2) = 0.56 : 22.4 = 0.025

n(CnH2n+1NH2) = n(CnH2n+1NH3Br) = 0.025

 

M(CnH2n+1NH3Br) = 3.5 : 0.025 = 140

 

12n+2n+1+14+3+80 = 140

14n = 42

n = 3

 

Ответ: C3H9N