Question

3 и 4. пожалуйста помогите) совсем не успеваю сделать

Answer 1

3.

$\left(\frac{m^2}{m+5}-\frac{m^3}{m^2+10m+25} \right): \left(\frac{m}{m+5}-\frac{m^2}{m^2-25} \right) =$

$\left(\frac{m^2}{m+5}-\frac{m^3}{(m+5)^2} \right): \left(\frac{m}{m+5}-\frac{m^2}{(m+5)(m-5)} \right) =$

$\left(\frac{m^2(m+5)}{(m+5)^2}-\frac{m^3}{(m+5)^2} \right): \left(\frac{m(m-5)}{(m+5)(m-5)}-\frac{m^2}{(m+5)(m-5)} \right) =$

$\left(\frac{m^3+5m^2-m^3}{(m+5)^2} \right): \left(\frac{m^2-5m-m^2}{(m+5)(m-5)} \right) =$

$\frac{5m^2}{(m+5)^2}: \frac{-5m}{(m+5)(m-5)} =$

$\frac{5m^2}{(m+5)^2} \cdot \frac{(m+5)(m-5)}{-5m}=$

$\frac{m}{m+5} \cdot \frac{m-5}{-1}= \frac{-m(m-5)}{m+5}=$

$\frac{-m^2+5m}{m+5}=\frac{5m-m^2}{m+5}$

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4.

$x-\frac{8}{x}=y\ /()^2$

$x^2-2\cdotx\cdot\frac{8}{x}+\frac{64}{x^2}=y^2$

$x^2-16+\frac{64}{x^2}=y^2$

$65-16=y^2$

$y^2=49$

$y= \pm 7$

$x-\frac{8}{x} \pm 7$