<em>∛32/(2^(²/₃))-√121=∛32/∛4-11=2∛4/∛4-11=2-11=<u>-9</u>.</em>
X^4-5x^2+4=0
x^2=t
t^2-5t+4=0
t1=1
t2=4
t1=1 => x^2=1 => x=+1;-1
t2=4 => x^2=4 => x=+2;-2
<span>(32)^x=16</span>
<span>(2^5)^x = 2^4</span>
<span>5x = 4</span>
<span>x = 0,8</span>
<span>
</span><span><span>(у^2 -4) * 3/(y-2)^2 = 3(y-2)(y+2)/(y-2)^2 = 3(y+2)/(y-2)</span></span>
Это разность кубов: а³-в³=(а-в)(а²+ав+в²)
Ответ: (7у²)³-1³=343у⁶-1.