2x-5=-1 при х=2
Находим
f (-1) = f (2·2-5) = 22-3·2+5=3
или так:
замена переменной
2 х-5=t ⇒ x = (t+5) / 2
f (t) = ((t+5) 2/4) - 3· ((t+5) / 2) + 5
f (t) = (t2+4t+15) / 4
f (-1) = (1-4+15) / 4=3
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