Question

Решить задачку по алгебре. Срочно!

Answer 1

У (t-2) и (t+1) общий знаменатель будет (t-2)*(t+1)=t^2-t-2;
$\frac{2*(t+1)+4(t-2)}{(t-2)(t+1)} = \frac{6t-6}{(t-2)(t+1)} =\frac{6(t-1)}{(t-2)(t+1)}$
t<>-1;
t<>2;

Answer 2

$\frac{2}{t-2}+ \frac{4}{t+1} = \frac{2t+2+4t-8}{(t-2)(t+1)} = \frac{6t-6}{(t-2)(t+1)} = \frac{6(t-1)}{(t-2)(t+1)}; t \neq -1 \\ \frac{6}{t-2}$