(2x-3)²(x-3)=(2x-3)(x-3)²
<span>(2x-3)²(x-3)-(2x-3)(x-3)²=0
</span>(2x-3)(x-3)(2x-3-x+3)=0
(2x-3)(x-3)*x=0
2x-3=0 или х-3=0 или х=0
2х=3 х=3
х₁=1,5 х₂=3 х₃=0
Ответ: 0; 1,5; 3
(-17tg4⁰ -2tg176⁰)/(4ctg274⁰-ctg94⁰)=
=(-17tg4⁰-2tg(180⁰-4⁰)/(4ctg(270⁰+4⁰)-ctg(90⁰+4⁰)=
=(-17tg4⁰+2tg4⁰)/(4tg4⁰-tg4⁰)=(-15tg4⁰)/3tg4⁰=-5;
1) -(9+30х +25х²) = -(3 +5х)²
2) -36b +81b² +4= (9b -2)²
3) -(-42xy +49x² +9y²) = -(7x -3y)²
4) -(0,36a⁴ +25b⁶ -6a²b³ ) = -(0,6a² -5b³)²
Если через дискриминант, то вот)
A) F(x) = x⁴/4 + 2x + C;
A(-1, 3)
3 = (-1)⁴/4 + 2 * (-1) + C = 0.25 - 2 + C;
3 = -1.75 + C => C = 3 + 1.75 = 4.75;
б) F(x) = x²/2 + 3x + C;
B(1, 2)
2 = 1/2 + 3*1 + C;
C = 2 - 3.5 = -1.5;
в) F(x) = 2x + x³/3 + C;
A(3, 1)
1 = 2*3 + 27/3 + C = 15 + C;
C = 1 - 15 = -14;