Question

Найдите корень уравнения 25^2x+5=125

Answer 1

(5^2)^(2х+5)=5^3;
4х+10=3;
4х=-7;
х=-7/4;
х=-1,75

Answer 2

$25^{2x+5}=125\\(5^2)^{2x+5}=5^3\\5^{4x+10}=5^3\\4x+10=3\\4x=-7\\x=-1,75$