Y=(x³+4)*√(1+x)/√4x y'=a'b+ab' (f(y))'=f'(y)*y' y'=(a/b)'=(a'b-b'a)/a²
y'=3x²*√(1+x)/√4x+(x³+4)*(1/2)*(√4x/√(1+x))*((4x-4x-4)/16x²)=
=
3^(-14)*3^8=3^(-6); 3^(-6) : 3^(-8)=3^2=9.
<span>3*(2-х)-(5 х +4)=0,4-16х
6-3х-5х-4=0,4-16х
2-8х=0,4-16х
16х-8х=0,4-2
8х=-1,6
х=-0,2</span>