Y = cosx + tgx
y' = -sinx + 1/cos²x
y = 5sin3x
y ' = 5·3cos3x = 15cos3x
y = 4x⁵ + tg3x - cos²x
y' = 4·5x⁴ + 3/cos²x + 2sinxcosx = 20x⁴ + sin2x + 3/cos²x
P.s.: u = cosx, v = u²
y' = u'v' = (cosx)'(u²)' = -sinx·2u = -sinx·2cosx = -2sinxcosx
(sinx)' = cosx
(cosx)' = -sinx
(tgx)' - 1/cos²x
(xⁿ)' = nxⁿ⁻¹
4m-3n=32,
<span>0,8m+2,5n=-6
умножаем второе на 5
4m+12.5n=-30
вычитаем первое
12.5n+3n=-30-32
15.5n=-62
n=-4
4m+12=32
4m=20
m=5</span>