![(x - 2) {}^{2} = 9 \\ \\ x {}^{2} - 4x + 4 - 9 = 0 \\ \\ x {}^{2} - 4x - 5 = 0 \\ \\](https://tex.z-dn.net/?f=%28x+-+2%29+%7B%7D%5E%7B2%7D++%3D+9+%5C%5C++%5C%5C+x+%7B%7D%5E%7B2%7D++-+4x+%2B+4+-+9+%3D+0+%5C%5C++%5C%5C+x+%7B%7D%5E%7B2%7D++-+4x++-+5+%3D+0+%5C%5C++%5C%5C+)
D = ( -4 )² - 4 * 1 * ( -5 ) = 16 + 20 = 36
![x1 = \frac{4 - 6}{2} \\ \\ x2 = \frac{4 + 6}{2} \\ \\ x1 = - 1 \\ \\ x2 = 5](https://tex.z-dn.net/?f=x1+%3D++%5Cfrac%7B4+-+6%7D%7B2%7D++%5C%5C++%5C%5C+x2+%3D++%5Cfrac%7B4+%2B+6%7D%7B2%7D++%5C%5C++%5C%5C+x1+%3D++-+1+%5C%5C++%5C%5C+x2+%3D+5)
~•~•~•ZLOY_TIGROVSKIY~•~•~•
250:2=125
125-12=113
250-113=137
У Кати 137 значков, а у Даши 113
1) F(x) = -cos2x/2 + C
-2 = 0 + C => C = -2
F(x) = -cos2x/2 - 2
2) F(x) = 2x² - 2x³ + x + C
2 = 0 + C => C = 2
F(x) = 2x² - 2x³ + x + 2
1) =5(x-3)-3(x-3)^2=(x-3)(5-3x+9)=(x-3)(14-3x)
2) =0,73(0,73+0,27)+0,27=0,73+0,27=1
3)12^5-18^4=2^5*6^5-3^4*6^4=6^4(32*6-81)=6^4(192-81)=6^4*111,
б) =6^4*111=6^3*666, (666:37)
4)2x^2-x=0, x(2x-1)=0, x=0, x=1/2
5(x-3)-(6-2x)^2=0, 5(x-3)-(2(3-x)^2=0, (x-3)(5-4(x-3))=0, (x-3)(8-4x)=0, x=3, x=2