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Удачи в учебе!!!!!!!!!!!!!
...= (√z - 2)² / (2-√z)(2+√z) = (√z - 2)/(2+√z)
1)=cos1/x*(1/x)`=cos1/x*(-1/x²)=-1/x²*cos1/x
2)ln`(5+8x)=(5+8x)`*1/(5+8x)=8/(5+8x)
3)ctg√x)`=-√x`/sin²√x=-1/2√xsin²√x
4)(tgx³)`=(x³)`/cos²x³=3x²/cos²x³
удачи вам.........ответ:0