Question

14^sinx= 0,5^cosx * 7^sinx Помогиите

Answer 1

$14^{sinx}=(\frac{1}{2})^{cosx}*7^{sinx}\\\frac{14^{sinx}}{7^{sinx}}=\frac{(2^{-1})^{cosx}*7^{sinx}}{7^{sinx}}\\2^{sinx}=2^{-cosx}\\sinx=-cosx\\ \frac{sin}{-cosx}=1\\-tgx=1\\tgx=-1\\x=-\frac{\pi}{4}$