6*х/3+6*х-1/2=6*4
2х+3(х-1) =24
2х+3х-3=24
5х-3=24
5х=24+3
5х=27
5х÷5=27÷5
х=27/5
Х=5 2/5
Дано: 2;-6;18
q=-6/2=-3 b₁=2
sₙ=b₁ (qₙ₋₁) / (q-1)
s₆=2 * ((-3) 6-1) / (-3-1) = 2*728 / (-4) = - 728/2=-364
sin^4a+2sin^2a*cos^2a+cos^4a-1= (sin^2a+cos^2a)^2 - 1 = 1^2 - 1 = 0
Ответ-----------------------------------------
а)4а^2-б^4
б)а(2+с)-б(2+с)=(2+с)(а-б).