Делаем по действиям:
1)1 + Ctg²t = 1/Sin²t
2) Sin²t * 1/Sin²t = 1
3) 1 - Sin²t = Cos²t
<span>в какой степени Х, столько и корней. 4х - 3х = 6+5; х = 11</span>
1/125*m³-27=(1/5*m-3)(1/25*m²+3/5*m+9)
27n³-64m³=(3n-4m)(9n²+12nm+16m²
x³+125y³=(x+5y)(x²-5xy+25y²)
8/27*a³-by=(2/3*a-∛(by))(4/9*a²+2/3*a∛(by)+∛(by)²)
8d³+1=(2d+1)(4d²-2d+1)
8b³-64a³=(2b-4a)(4b²+8ba+16a²)
Вот решение: ( 6y )^2 = 36y^2