CH3COONa+NaOH=CH4+Na2CO3
2CH4=C2H2+3H2 (t 1000 C)
3C2H2=C6H6 (t 400 C)
C6H6+Cl2=C6H5Cl+HCl
C6H5Cl+H2O=C6H5OH+HCl
C6H5OH+3HNO3=C6H2(NO2)3OH+H2O
дано
n(CaCL2) = 0.3 mol
--------------------------------
m(CaCO3)-?
CaCL2+Na2CO3-->2NaCL+CaCO3↓
n(CaCL2) = n(CaCO3) = 0.3 mol
M(CaCO3) = 100 g/mol
m(CaCO3) = n*M = 0.3*100 = 30 g
ответ 30 г
дано
n(NaCL) = 0.8 mol
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m(Na2CO3) -?
CaCL2+Na2CO3--->2NaCL+CaCO3
n(Na2CO3) = n(NaCL) / 2 = 0.8 / 2 = 0.4 mol
M(Na2CO3) = 106 g/mol
m(Na2CO3) = n*M = 0.4 * 106
m(Na2CO3) = 42.4 g
ответ 42.4 г
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Б) родниковая вода вроде самое чистое
Mr( H3PO4)=98
Моль= m/Mr=29,4/98=0.3
N=V*Na=6.02*10(в 23 степ)*0.3=1.806*10(в 23степ.)