<span>а^6,21/а^2,28*а^3,43=a^ (6,21-2,28 -3,43) = a^0,5 = </span>√a = √ (10/11 )= √110/11<span>
при а=10/11</span>
2 вариант на фотографии правильный
Q`(x)=1/3*2(5-х2)*(-2)=-4/3(5-2х)
йё(2)=-4/3*(5-2*2)=-4/3
Пусть 5x^2 + x - 1 = t , тогда
t^2 - t - 2 = 0
D = 1 + 4*2 = 9
t₁ = (1+ 3 )/2 = 2;
t₂ = ( 1 - 3)/2 = - 1;
Получим 2 случая
1)
5x^2 + x - 1 = 2
5x^2 + x - 3 = 0
D = 1 + 4*5*3 = 61
x₁ = ( - 1 + √61)/10;
x₂ = ( - 1 - √61)/10
2)
5x^2 + x - 1 = - 1
5x^2 + x = 0
x (5x + 1) = 0
x₃= 0 ;
5x + 1 = 0 ==> x₄ = - 1/5 = - 0,2