x³*1,4x⁶y⁵=1,4x⁹y⁵;
1,6a²c * (-2ac²)=-3,2a³c³
F(x)=-2/(x-3)
f(x-1)=-2/(x-4)
f(x+4)=-2/(x+1)
-2/(x-4)+2/(x+1)=k*4/[(x-4)(x+1)
4k=-2(x+1)+2(x-4)
4k=-2x-2+2x-8
4k=-10
k=-2,5
<span>1.(4x-3)^2-16=(4х-3-4)(4х-3+4)=(4х-7)(4х+1)
2.(4</span><span>x-3)^2-16=0
</span><span>(4х-3-4)(4х-3+4)=0
(4х-7)(4х+1)=0
4х-7=0 или 4х+1=0
х=1,75 х=-0,25
ответ:</span><span>х=1,75 х=-0,25</span>
А)4
б)1,75
в)1
г)10/3
..........
<span>(а+2б)^3-(а+2б)^3=
a</span>³+6a²b+12ab²+8b³-a³-6a²b-12ab²-8b³=0