55555555555555555555555555555555555555555555555555 25 2
дано
m(ppa H2SO4) = 320 g
W(H2SO4) = 5%
+m(H2O) = 20 g
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W1(H2SO4)-?
m общ (ppa H2SO4) = 320 + 20 = 340 g
m(H2SO4) = 320 *5% / 100% = 16 g
w1(H2SO4) = m(H2SO4) / m общ(ppa H2SO4) *100% = 16 / 340*100% = 4.7%
ответ 4.7 %
2Fe+6HCL=2FeCl3+3H2
FeCl3+3KOH=Fe(OH)3+3KCl
2Fe(OH)3=Fe2O3+3H2O
2Fe2O3=Fe+3O2
Fe+2HCl=FeCl2+H2
<span>FeCl2+2NaOH=Fe(OH)2+2NaCl</span>