A) 4*(c+5)=c+2
4c+5=c^2+4c+
c^2-1=0
c=+1 и c=-1
Б)d^2-2d+1=d+5
d^2-3d-4=0
D=9+16=25
d1=(3+5)/2=4
d2=(3-5)/2=-1
Г) 3u+1-4-u+1=0
2u-2=0
2u=2
u=1
<span>1)sin(x-pi/4)=0</span>
t=<span>x-pi/4</span>
<span>sint=0</span>
<span>1.t=0+2pi*k</span>
x-pi/4=0
x=pi/4
2.t=pi+2pi*k
pi=x-pi/4
x=5pi/4+2pi*k
3)<span>sinx(3x+pi/3)=1</span>
<span>t=<span>3x+pi/3</span></span>
<span><span>sint=1</span></span>
<span><span>t=pi/2</span></span>
<span><span>3x+pi/3=pi/2</span></span>
<span><span>x=pi/18</span></span>
<span><span>5)<span>tg(x-pi/6)=-√3</span></span></span>
<span><span><span>t=x-pi/6</span></span></span>
<span><span><span>tgt=-√3</span></span></span>
<span><span><span>t=-pi/3+2pi*k . k=Z</span></span></span>
<span><span><span>t=2pi/3+2pi*k . k=Z</span></span></span>
Х²-2х+3х-6-(х²-х)=х²+х-6-х²+х=2х-6=2*(х-3)
Так как х=2\3,тогда
2*(х-3)=2*(2\3-3)=2*(2-3*3\3)=2*(2-9\3)=2*(-7\3)=-14\3
Вот решение уравнения если правильное условие