Question

Найдите такие числа а и б что равенство 7x-4=a (x-2)+b (x+3) выполняется одновременно при x=1и при x =-1

Answer 1

$\left \{ {{7*1-4 = a(1-2)+b} \atop {7*(-1)-4 = a(-1-2)+b}} \right. =\ \textgreater \ \left \{ {{3 = -a+b} \atop {-11 = -3a+b}} \right. =\ \textgreater \ \left \{ {{a = b-3} \atop {-11 = -3*(b-3)+b}} \right. =\ \textgreater \ \\ \\ \left \{ {{a = b-3} \atop {2b = 9+11}} \right. =\ \textgreater \ \left \{ {{a = 10-3} \atop {b = 10}} \right. =\ \textgreater \ \\ \\ a=7, b=10.$