ОДЗ
x ≥ 0
( - 2x + 3)^2 = x^2
(-2x)^2 - 12x + 9 - x^2 = 0
4x^2 - 12x + 9 - x^2 = 0
3x^2 - 12x + 9 = 0 /:3
x^2 - 3x + 2 = 0
D = 9 - 8 = 1
x1 = ( 3 + 1)/2 = 4/2 = 2
x2 = (3 - 1)/2 = 2/2 = 1
Ответ
1; 2
F(x)=4xˇ3 +2x-4
S(4xˇ3+2x-4)dx= xˇ4+xˇ2-4x+c
xˇ4+xˇ2-4x+c =g(x)
g(2)=0
2ˇ4+2ˇ2-4.(2)+c = 0
16+4-8+c=0,c=-12
g(x)=xˇ4+xˇ2-4x-12
14/25+3/2=7/25+3/1=10/25=2/5