=2a^6+4a^5b+2a^4b^2-5a^5b-10a^4b^2-5a^3b^3-3a^4b^2-6a^3b^3-3a^2b^4+a^2b^3+2a^2b^4+ab^5-4a^2b^4-8ab^5-4b^6=
2a^6-a^5b-11a^4b^2-10a^3b^3-7ab^5-4b^6
5. 3a²-3ab+2ab-b²=3a²-ab-b²
6. 3c²-6c-2c-4=3c²-8c-4
Sin 2x = 2 sin x cos x
sin (pi -x) = sin x
----------------------------
cos(pi/33)*cos(2pi/33)*cos(4pi/33)*cos(8pi/33)*cos(16pi/33) = sin(pi/33)*cos(pi/33)*cos(2pi/33)*cos(4pi/33)*cos(8pi/33)*cos(16pi/33) / sin(pi/33) = sin(2pi/33)*cos(2pi/33)*cos(4pi/33)*cos(8pi/33)*cos(16pi/33) / 2sin(pi/33) = sin(4pi/33)*cos(4pi/33)*cos(8pi/33)*cos(16pi/33) / 4sin(pi/33) = sin(8pi/33)*cos(8pi/33)*cos(16pi/33)/ 8sin(pi/33) = sin(16pi/33)*cos(16pi/33)/ 16sin(pi/33) = sin(32pi/33) / 32pi(33) = sin(pi-pi/33)/16sin(pi/33) = sin(pi/33) / 32sin(pi/33) = 1/32
Sinx=√2/2
x=(-1)^n*π/4 + πn, n∈Z
Если "расписать", то
![\left \{ {{x=Pi/4 + 2Pi*n} \atop {x=3Pi/4 + 2Pi*n}} \right.](https://tex.z-dn.net/?f=+%5Cleft+%5C%7B+%7B%7Bx%3DPi%2F4+%2B+2Pi%2An%7D+%5Catop+%7Bx%3D3Pi%2F4+%2B+2Pi%2An%7D%7D+%5Cright.+)
, n∈Z
Это все корни, но нас волнует отрезок от 0 до 3π
Ответ: π/4, 3π/4, 9π/4, 11π/4