![3cos2x+4+11sinx = 0 \\ 3(1 - 2sin^{2}x) +4+11sinx = 0 \\ 3 - 6sin^{2}x+4+11sinx = 0 \\ - 6sin^{2}x+11sinx+7 = 0 \\ 6sin^{2}x-11sinx-7 = 0 \\ D = 121 + 4*6*7 = 121 + 168 = 289 = 17^{2} \\ sinx = \frac{11 + 17}{12} = \frac{28}{12} \\](https://tex.z-dn.net/?f=3cos2x%2B4%2B11sinx+%3D+0+%5C%5C+%0A3%281+-+2sin%5E%7B2%7Dx%29+%2B4%2B11sinx+%3D+0+%5C%5C+%0A3+-+6sin%5E%7B2%7Dx%2B4%2B11sinx+%3D+0+%5C%5C+%0A-+6sin%5E%7B2%7Dx%2B11sinx%2B7+%3D+0+%5C%5C+%0A6sin%5E%7B2%7Dx-11sinx-7+%3D+0+%5C%5C+%0AD+%3D+121+%2B+4%2A6%2A7+%3D+121+%2B+168+%3D+289+%3D+17%5E%7B2%7D++%5C%5C+%0Asinx+%3D++%5Cfrac%7B11+%2B+17%7D%7B12%7D+%3D+%5Cfrac%7B28%7D%7B12%7D++%5C%5C+)
(невозможно , т.к. | sin x | ≤ 1)
или
![sinx = \frac{11 - 17}{12} = \frac{-6}{12} = - \frac{1}{2}\\ x=(-1)^{n}(-\frac{\pi }{6})+\pi n,](https://tex.z-dn.net/?f=sinx+%3D+%5Cfrac%7B11+-+17%7D%7B12%7D+%3D+%5Cfrac%7B-6%7D%7B12%7D+%3D+-+%5Cfrac%7B1%7D%7B2%7D%5C%5C+%0Ax%3D%28-1%29%5E%7Bn%7D%28-%5Cfrac%7B%5Cpi+%7D%7B6%7D%29%2B%5Cpi+n%2C++)
где n ∈ Z.
![x=(-1)^{n+1}\frac{\pi }{6}+\pi n,](https://tex.z-dn.net/?f=x%3D%28-1%29%5E%7Bn%2B1%7D%5Cfrac%7B%5Cpi+%7D%7B6%7D%2B%5Cpi+n%2C)
где n ∈ Z.
Производная равна:
y'=x^9-x^6+3^0.5
tg(alpha)=y'(x0)=1-1+3^0.5=3^0.5
<span>Тогда угол равен alpha=pi/3</span>
7! = 1*2*3*4*5*6*7 = 24*30*7 = 720*7 = 5040
8! = 7! * 8 = 5040 * 8 = 40320
6! - 5! = 5! * 6 - 5! = 5! * (6-1) = 5! * 5 = 120*5 = 600
5! / 5 = 4! * 5 / 5 = 4! = 24
Метод равносильного перехода из ✓f(x) > g(x)
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