Ответ:
Объяснение:2sinx/2·cosx/2+3(cos²x/2-sin²x/2)=2(sin²x/2+cos²x/2);
cos²x/2-5sin²x/2+2sinx/2·cosx/2=0;
5sin²x/2-2sinx/2·cosx/2-cos²x/2=0 ║ : cos²x/2≠0,
5tg²x/2-2tg x/2-1=0; tg x/2=t,
5t²-2t-1=0, t1=(1+√6)/5 , t2=(1-√6)/5;
1)tg x/2=(1+√6)/5, x/2=arc tg(1+√6)/5+πn,n∈z x=2arc tg(1+√6)/5 +2πn,n∈z
2)tg x/2=(1-√6)/5, x/2=arc tg(1-√6)/5 +πk,k∈z, x=2arc tg(1-√6)/5 +2πk,k∈z
1) F(x)= 1/3x^3 + 2x^2 - x + c
2) F(x)= 0,5 e^2x
3) F(x)= (7 * (x/7 - 2)^5)/5
интеграл:
1) F=1/5 x^5 => 32/2 + 1/5 = 7,2
2) F=-cosX => -cos3 - cos1 = -cos3 - 1
3) F=3x^2 - 0,5x^2 => (3*36 - 6) - 0 = 102
вроде правильно :D
<span>(-3а-4ах +2)-(11а -14ах)=-3a-4ax+2-11a+14ax=<span>-14a+10ax+2
</span></span><span> 3у</span>²<span>(у</span>³<span>+1)=3y</span>²y³+3y²=3y⁵+3y²<span>
</span>
(1/6 + 1 1/10) * 24 = (5/30 + 1 3/30) * 24 = 1 8/30 * 24 = 1 4/15 * 24 = 19/15 * 24 = (19 * 24)/15 = (19 * 8)/5 = 152/5 = 304/10 = 30,4
Ответ: 30,4.