Выразим у через х
у=3у-4
-2у=-4
2у=4
У=2
Х=2 т. к у=х
F(x) = cos5x · cos(x + π/6)
g(x) = sin5x · sin(x + π/6) + 0.5√3
cos5x · cos(x + π/6) = sin5x · sin(x + π/6) + 0.5√3
cos5x · cos(x + π/6) - sin5x · sin(x + π/6) = 0.5√3
cos (6x + π/6) = 0.5√3
6x + π/6 = ⁺₋ π/6 + 2πn n∈Z
1) 6x₁ + π/6 = + π/6 + 2πn n∈Z 2) 6x₂ + π/6 = - π/6 + 2πn n∈Z
1) 6x₁ = 2πn n∈Z 2) 6x₂ = - π/3 + 2πn n∈Z
1) x₁ = πn/3 n∈Z 2) x₂ = - π/18 + πn/3 n∈Z
Ответ: x₁ = πn/3 n∈Z
x₂ = - π/18 + πn/3 n∈Z
Исходное не пишу
1) 14 4/5+4/15=14 12/15+4/15=14 16/15=15 1/15
2) 2 2/3:4=8/3:4=2/3
3) 15 1/15:22 3/5=226/15:113/5=(226*5)/(15*113)=2/3
4) 2/3+2/3=4/3=1 1/3
q= 1/6 : 1/3 = 1/6 * 3/1 = 1/2