Ответ.......................264
y=2*(x+2)+4. ///////////////////////////////////////////////////////////////
В) <span>.
2*{[cos(x + 3x)/2] * [cos(x - 3x)/2]}= cos2x
2*[cos2x*cosx] - cos2x = 0
cos2x(2cosx - 1) = 0
1) cos2x = 0
2x = </span>π/2 + πn, n∈Z
<span>x1 = </span>π/4 + (πn)/2, n ∈Z
<span>2) 2cosx - 1 = 0
cosx = 1/2
x = (+ -) arccos(1/2) + 2</span>πk, k∈Z
<span>x2 = (+ -)*(</span>π/3) + 2πk, k∈Z <span>
</span>
6y + 3x = 5
5x + 3y = - 1
-----------------
- 6y - 3x = - 5
10x + 6y = - 2
7x = - 7
x = - 1
- 5 + 3y = - 1
3y = 4
y = 1 1/3
Ответ ( - 1 ; 1 1/3 )