Tg(Х+3Х)=1, tg 4х =1, 4х = π/4 +πn, n∈Z, x=π/16 + πn/4, n∈Z
Открываем скобки
6x^2+21x-10x-35=6x^2-9x+2x-3+4x
6x^2+11x-35=6x^2-3x-3
11x-35=-3x-3
14x=-3+35
14x=32
x=32/14
x=16/7
Ответ ответ ответ ответ ответ ответ
<span>1) x^2-4x+3=0
х</span>² -2х*2 +4 - 4 +3 = 0
<span>(х-2)</span>² = 1
<span>х -2 = 1 или х -2 = -1
х = 3 х = 1
2)x^2 - 6x+5=0
х</span>² -2х*3 +9 -9 +5 = 0
<span>(х-3) = 4
х-3 = 2 или х -3 = -
х = 5 х = -1
3)x^2+8x-20=0
х</span>² +2х*4 +16 -16 -20 = 0
<span>(х+4)</span>² = 4
<span>х +4 = 2 или х +4= -2
х = -2 х = -6
4)x^2+12x+32=0
х</span>² +2х*6 +36 -36 +32 = 0
<span>(х +6)</span>² = 4
<span>х +6 = 2 или х +6 = -2
х = -4 х = -8
5)x^2-2x-15=0
х</span>² -2х*1 +1 -1 -15 = 0
<span>(х-1)</span>² = 16
<span>х-1 = 4 или х-1 = -4
х = 5 х = -3
6)X^2-4x-45=0
х</span>² -2х *2 +4 -4 -45 =0
(х-2)² = 49
х-2 = 7 или х -2 = -7
х = 9 х = -5
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2)
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3)
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4)
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5)
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6)
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