Question

( х-5 )^2 - 2( x-5 )=8

Answer 1

(x-5)²-2(x-5)=8
x²-10x+25-2x+10-8=0
x²-12x+27=0

$\sqrt{D}= \sqrt{(-12)^2-4*27} = \sqrt{144-108} = \sqrt{36} =6$

x₁ = $\frac{12+6}{2} = \frac{18}{2} =9$

x₂ = $\frac{12-6}{2} = \frac{6}{2} =3$