10(3х-2)-3(5х+2)+5(11-4х)=25
30х-20-15х-6+55-20х=25
-5х+29=25
-5х=25-29
-5х=-4 (делим все на -5)
х=0.8
1) √75/√3=√(75/3)=√25=5
√(-3)⁸=√3⁸=3⁴=81
4)
(1+√5)²=1+5+2√5=6+2√5=2(3+√5)
(√5-√3)(√5+√3)=√5²-√3²=5-3=2
![\frac{(3 \sqrt{14}+ \sqrt{7})* \sqrt{7} }{7} -2 \sqrt{2} = \frac{21 \sqrt{2}+7 }{7} -2 \sqrt{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B%283+%5Csqrt%7B14%7D%2B+%5Csqrt%7B7%7D%29%2A+%5Csqrt%7B7%7D+++%7D%7B7%7D+-2+%5Csqrt%7B2%7D+%3D+%5Cfrac%7B21+%5Csqrt%7B2%7D%2B7+%7D%7B7%7D+-2+%5Csqrt%7B2%7D+)
![\frac{21 \sqrt{2} +7-14 \sqrt{2} }{7} = \frac{7( \sqrt{2}+1) }{7} = \sqrt{2} +1](https://tex.z-dn.net/?f=+%5Cfrac%7B21+%5Csqrt%7B2%7D+%2B7-14+%5Csqrt%7B2%7D+%7D%7B7%7D+%3D+%5Cfrac%7B7%28+%5Csqrt%7B2%7D%2B1%29+%7D%7B7%7D+%3D+%5Csqrt%7B2%7D+%2B1)
6)
![4 \sqrt{ \frac{7}{2} } - \sqrt{14} - \sqrt{14} = 4 \sqrt{3,5} -2 \sqrt{14} =2(2 \sqrt{3,5} - \sqrt{14} )](https://tex.z-dn.net/?f=4+%5Csqrt%7B+%5Cfrac%7B7%7D%7B2%7D+%7D+-+%5Csqrt%7B14%7D+-+%5Csqrt%7B14%7D+%3D+4+%5Csqrt%7B3%2C5%7D+-2+%5Csqrt%7B14%7D+%3D2%282+%5Csqrt%7B3%2C5%7D+-+%5Csqrt%7B14%7D+%29)
√2+√2=2√2
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3 ^ ( Х + 2 ) - 3 ^ ( Х ) < 24
3 ^ Х • ( 3^2 - 1 ) < 24
3 ^ Х < 24 : 8
3 ^ Х < 3
Х < 1
( - бесконечность; 1 )