А) (2х+а)(с+3)
Б) (х^2-9)(х^2-1)
С) (х-1)(y+x)
5x-3 < 3x-5
5x-3x < 3-5
2x < -2
x < -2:2
x < -1
x ∈ (-∞; -1)
2x^3 - x^2 - 18x + 9 = 0
x^2 (2x - 1) - 9(2x - 1) = 0
(x^2 - 9) (2x - 1) = 0
x^2 - 9 = 0
x^2 = 9
x1 = - 3
x2 = 3
2x - 1 = 0
2x = 1
x3 = 1/2 = 0, 5
Ответ:
- 3; 0,5 ; 3
Х+4=15, х=11
2у+1=32, 2у=31,у=15.5
5u-7=-42, 5u=-35,u=7
10-c=12 , c=-2