Отрезки касательных, проведенных из одной точки, равны.
Пусть х - одна часть.
Значит, AK = AE = 2x
CT = CE = 2x
BT = BK = 3x
2x · 4 + 3x · 2 = 15
8x + 6x = 15
14x = 15
x = 15/14
AB = BC = 5x = 75/14
AC = 4x = 30/7
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18−<span>5<span>(<span>+3</span>)</span></span></span>><span>1−<span>7</span></span></span><span><span>18−<span>5<span>(<span>x+3</span>)</span></span></span>><span>1−<span>7x</span></span></span></span><span><span><span><span>18−<span>5</span></span>−15</span>><span>1−<span>7</span></span></span><span><span><span>18−<span>5x</span></span>−15</span>><span>1−<span>7x</span></span></span></span><span><span><span>3−<span>5</span></span>><span>1−<span>7</span></span></span><span><span>3−<span>5x</span></span>><span>1−<span>7x</span></span></span></span><span><span><span><span><span>−5</span></span>+<span>7</span></span>><span>1−3</span></span><span><span><span><span>−5</span>x</span>+<span>7x</span></span>><span>1−3</span></span></span><span><span><span>2</span>><span>−2</span></span><span><span>2x</span>><span>−2</span></span></span>x> - 1 <span><span>>−1
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И так функция берётся от -4. -4<0.
Значит нам нужно выполнить следующею операцию:
Ответ: -16