W(C)= 75\%
w(H)=25\%
M(CxHy)= 8*2=16г/моль
x:y=75/12:25/1= 6.25/6025:25 /6.25=1:4 M(CH4)=16
CH3COOH
Mr(CH3COOH)=12+3+12+16+16+1=60
w(O)=32/60•100%=53,3%
MnCl2 + 2 NaOH → Mn(OH)2 + 2 NaCl
4Na + O2 = 2Na2O
n (Na) = m/M = 4.6/23 = 0.2 моль
n (O2) = (1/4)n (Na) = (1/4) * 0.2 = 0.05 моль
V (O2) = n * Vm = 0.05 * 22.4 = 1.12л
Ответ: V (O2) = 1.12л