Решение смотри на фотографии
<span>4x^2-5x-6=0
D = 25 + 4*4*6 = 121
x1 = (5 - 11)/8 = -6/8 = -3/4
x2 = (5+11)/8 = 16/8 = 2
</span><span>2)-3x^2=x
-3x^2 - x = 0
3x^2 + x = 0
x(3x + 1) = 0
x = 0; x = -1/3
</span>
∫(4x -1/x^2 -2x -3)dx=4x^2/2 -(-1/x) -2x^2/2 -3x = 2x^2+(1/x) -x^2 -3x =
f'(x)=2,5*x√x; f'(x)=2x*√x+x^2/2√x=2,5x√x;
h(x)'=3x^2/4-2
или если 4-2х в знаменателе
(3x^2(4-2x)+x^3*2)/(4-2x)^2=(12x^2-4x^3)/(4-2x)^2=4x^2(3-x)/(4-2x)^2
49+4x²+28x=2*(x²+4x+3)
4x²-2x²+28x-8x-6=0
2x²+20x-6=0
x²+10x-3=0
D=100+12=112
x1=(-10-√112)/2=-5-√28 x2=-5+√28