Πх/6 = arctg√3 + πk , k ∈ Z
πx/6 = π/3 + πk , k ∈ Z
x/6 = 1/3 + k , k∈Z
x = 2 + 2k , k ∈Z
x = -2
А) 4х+12=5х+10
9х=-2
х=-2/9
б) -2х+10+3х-12=4х+1
-3х=-1
х=1/3
в) 3х-3=2х+4
5х=7
х=1 2/5
г) 3х-15-2х-8=-5х+1
6х=24
х=24:6
х=4
(2a-3b)-(a-2b)=2a-3b-a+2b=a-b
1) x1=0, x2=2
2)x=-9, x2=1