Эти числа являются членами арифметической прогрессии
первый член 103 ... последний 495
сумма равна произведению полусуммы первого и последнего члена и количству членов
найдем кол-во членов
500-100=400
400/7 = 57
сумма=(103+495)/2 * 57 = 17043
(3с+9)×с+3
========= (это знак дроби)
6с×2с4(степень)
выносим с первых скобок 3.
3(с+3)×(с+3)
===========
2с(3×с3) (3 это степень), а выносим, со вторых скобок 2с.
(дальше я не уверена, правильно ли, но всё же)
3(с+3)2 ( 2 это квадрат над скобкай ( с+3 )
======
2с(3×с3) ( 3 это степень "с")
<span><span><span>1 × 1 = 1
1 × 2 = 2
1 × 3 = 3
1 × 4 = 4
1 × 5 = 5
1 × 6 = 6
1 × 7 = 7
1 × 8 = 8
1 × 9 = 9
1 × 10 = 10
</span><span>
2 × 1 = 2
2 × 2 = 4
2 × 3 = 6
2 × 4 = 8
2 × 5 = 10
2 × 6 = 12
2 × 7 = 14
2 × 8 = 16
2 × 9 = 18
2 × 10 = 20
</span><span>
3 × 1 = 3
3 × 2 = 6
3 × 3 = 9
3 × 4 = 12
3 × 5 = 15
3 × 6 = 18
3 × 7 = 21
3 × 8 = 24
3 × 9 = 27
3 × 10 = 30
</span><span>
4 × 1 = 4
4 × 2 = 8
4 × 3 = 12
4 × 4 = 16
4 × 5 = 20
4 × 6 = 24
4 × 7 = 28
4 × 8 = 32
4 × 9 = 36
4 × 10 = 40
</span><span>
5 × 1 = 5
5 × 2 = 10
5 × 3 = 15
5 × 4 = 20
5 × 5 = 25
5 × 6 = 30
5 × 7 = 35
5 × 8 = 40
5 × 9 = 45
5 × 10 = 50
</span></span><span><span> × 6
</span><span> × 7
</span><span> × 8
</span><span> × 9
</span><span> × 10
</span></span><span><span>
6 × 1 = 6
6 × 2 = 12
6 × 3 = 18
6 × 4 = 24
6 × 5 = 30
6 × 6 = 36
6 × 7 = 42
6 × 8 = 48
6 × 9 = 54
6 × 10 = 60
</span><span>
7 × 1 = 7
7 × 2 = 14
7 × 3 = 21
7 × 4 = 28
7 × 5 = 35
7 × 6 = 42
7 × 7 = 49
7 × 8 = 56
7 × 9 = 63
7 × 10 = 70
</span><span>
8 × 1 = 8
8 × 2 = 16
8 × 3 = 24
8 × 4 = 32
8 × 5 = 40
8 × 6 = 48
8 × 7 = 56
8 × 8 = 64
8 × 9 = 72
8 × 10 = 80
</span><span>
9 × 1 = 9
9 × 2 = 18
9 × 3 = 27
9 × 4 = 36
9 × 5 = 45
9 × 6 = 54
9 × 7 = 63
9 × 8 = 72
9 × 9 = 81
9 × 10 = 90
</span><span>
10 × 1 = 10
10 × 2 = 20
10 × 3 = 30
10 × 4 = 40
10 × 5 = 50
10 × 6 = 60
10 × 7 = 70
10 × 8 = 80
10 × 9 = 90
10 × 10 = 100</span></span></span>
<span><span>x4</span> - 12<span>x</span></span>²<span> + 11 = 0</span>
<span>Сделаем замену </span>y<span> = </span>x², тогда биквадратное уравнение примет вид
<span><span>y</span></span>²<span> - 12y + 11 = 0</span>
Для решения этого квадратного уравнения найдем дискриминант:
D = (-12)²<span> - 4·1·11 = 100</span>
<span><span><span>
</span><span> 12 - √100</span>
у1 = --------------- = 1
2 * 1
12 + </span></span>√100
<span><span>у2 = ----------------- = 11
2 * 1
</span></span>
<span><span>x</span></span>²<span><span> = 1
х</span></span>² = 11
<span><span>х1 = </span></span>√1 =1
<span><span>х2 = - </span></span>√1 = -1
<span><span>
х3 = </span></span>√11
<span><span><span>х4 = - </span></span></span>√11